x^2+80x-200=0

Solution for x^2+80x-200=0 equation:

x^2+80x-200=0

a = 1; b = 80; c = -200;
Δ = b2-4ac
Δ = 802-4·1·(-200)
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-60\sqrt{2}}{2*1}=\frac{-80-60\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+60\sqrt{2}}{2*1}=\frac{-80+60\sqrt{2}}{2}
$